Re: subtitute of mysql_error()

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Whatever made you think mysql_error() wasn't working, that was wrong.

Because mysql_error() works just fine.

On Wed, August 1, 2007 1:09 am, Patrik Hasibuan wrote:
> Dear my friends....
>
> What is the substitute of mysql_error() ?
>
> This line of my code does not work anymore:
> 		$hslgbr=mysql_query("$sqlgbr","$konek") or die ( mysql_error() );
>
> Thank you very much in advance.
> --
> Patrik Hasibuan <patrikh@xxxxxxxxxxxxxxxxxxxxx>
> Junior Programmer
>
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>


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Some people have a "gift" link here.
Know what I want?
I want you to buy a CD from some indie artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?

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