Patrik Hasibuan wrote:
Dear my friends....
What is the substitute of mysql_error() ?
This line of my code does not work anymore:
$hslgbr=mysql_query("$sqlgbr","$konek") or die ( mysql_error() );
Thank you very much in advance.
In what way does it "not work anymore"?
The code above is perfectly valid. Incidentally, there is no need to put
a single variable in quotes - all this does is cause extra pointless
work for the PHP engine.
-Stut
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http://stut.net/
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