Re: showing source

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yup, highlight_file($file_name) is your magical answer.
http://ca.php.net/highlight_file
Make sure this function will only access specific directories.

-- 
itoctopus - http://www.itoctopus.com
""M.Sokolewicz"" <tularis@xxxxxxx> wrote in message 
news:464D716B.7040702@xxxxxxxxxx
> Why don't you use:
> highlight_file(__FILE__) ?
>
> - tul
>
> James Lockie wrote:
>> This almost works but all my < and > are replaced with "".
>>
>>        // open this file to show the source
>>        if (($fh = fopen( __FILE__, 'r' )) === FALSE){
>>            die ('Failed to open source file (' . $_FILE_ . ') for 
>> reading!');
>>        } else {
>>            $tags  = array( "<", ">" );
>>            $safe_tags = array( "\\<", "\\>" );
>>
>>            print "<pre>\n";
>>
>>            // read the file line by line
>>            while (! feof( $fh )) {
>>                $currentLine = fgets( $fh, 255 );
>>                $noTags = str_replace( $tags, $safeTags, $currentLine );
>>                print $noTags;
>>            }
>>
>>            fclose( $fh );
>>            print "</pre>\n";
>>        } 

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