Re: echo date('Y-m-d', $mydata->timestamp);

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Use the MySQL function that converts timestamp into Unixtime.

Or, better yet, use the MySQL function that outputs exactly the date
format you want, without dinking around with Unix timestamp in the
middle.

http://dev.mysql.com/

Search for date_format() I do believe.

It's gonna be a whole lot like PHP 'date' function, only with % signs,
as I recall.

On Sun, April 22, 2007 1:33 am, John Taylor-Johnston wrote:
>
> It is actually a generated timestamp in MySQL.
> timestamp(14)
> Now what? I was hoping to avoid:
> |echo substr(|$mydata->timestamp|, 0, 8);
>
> John
>
> |Richard Lynch wrote:
>> On Sun, April 22, 2007 1:05 am, John Taylor-Johnston wrote:
>>
>>> $mydata->timestamp = "20070419162123";
>>>
>>> echo date('Y-m-d', $mydata->timestamp);
>>>
>>>
>>> result: 2038-01-18
>>>
>>> ?? What is wrong?? Should be 2007-04-19?
>>>
>>
>> date() takes a Unix timestamp as its input.
>>
>> Unix timestamps are measured as number of seconds from Jan 1, 1970,
>> midnight, GMT, the birth of Disco.
>> [that last was a joke...]
>>
>> You are handing it a pre-formatted date-stamp in YYYYMMDDHHIISS
>> format...
>>
>> You could do something like:
>> $t = '20070419162123';
>> $year = substr($t, 0, 4);
>> $month = substr($t, 4, 2);
>> $day = substr($t, 6, 2);
>> $hour = substr($t, 8, 2);
>> $minutes = substr($t, 10, 2);
>> $seconds = substr($t, 12, 2);
>> echo date(mktime($month, $day, $year, $hour, $minutes, $seconds));
>>
>> I suspect strtotime() *might* handle your input and give you a Unix
>> timestamp...
>>
>> I also suspect whatever you needed a Unix timestamp for in the first
>> place could have been achieved easier before you got painted into
>> this
>> corner...
>>
>>
>


-- 
Some people have a "gift" link here.
Know what I want?
I want you to buy a CD from some indie artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?

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