On Sun, April 22, 2007 1:05 am, John Taylor-Johnston wrote:
> $mydata->timestamp = "20070419162123";
>
> echo date('Y-m-d', $mydata->timestamp);
>
>
> result: 2038-01-18
>
> ?? What is wrong?? Should be 2007-04-19?
date() takes a Unix timestamp as its input.
Unix timestamps are measured as number of seconds from Jan 1, 1970,
midnight, GMT, the birth of Disco.
[that last was a joke...]
You are handing it a pre-formatted date-stamp in YYYYMMDDHHIISS format...
You could do something like:
$t = '20070419162123';
$year = substr($t, 0, 4);
$month = substr($t, 4, 2);
$day = substr($t, 6, 2);
$hour = substr($t, 8, 2);
$minutes = substr($t, 10, 2);
$seconds = substr($t, 12, 2);
echo date(mktime($month, $day, $year, $hour, $minutes, $seconds));
I suspect strtotime() *might* handle your input and give you a Unix
timestamp...
I also suspect whatever you needed a Unix timestamp for in the first
place could have been achieved easier before you got painted into this
corner...
--
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Know what I want?
I want you to buy a CD from some indie artist.
http://cdbaby.com/browse/from/lynch
Yeah, I get a buck. So?
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