Hello !
I have problem with access in mysql
it is my code:
<html>
<head><title>SQL Query Sender</title></head>
<body>
<?php
$host="";
$user="";
$password="";
/* Section that executes query */
if(@$_GET['form'] == "yes")
{
mysql_connect($host,$user,$password);
mysql_select_db($_POST['database']);
$query = stripSlashes($_POST['query']);
$result = mysql_query($query);
echo "Database Selected: <b>{$_POST['database']}</b><br>
Query: <b>$query</b><h3>Results</h3><hr>";
if($result == 0)
echo "<b>Error ".mysql_errno().": ".mysql_error().
"</b>";
elseif (@mysql_num_rows($result) == 0)
echo("<b>Query completed. No results returned.
</b><br>");
else
{
echo "<table border='1'>
<thead>
<tr>";
for($i = 0;$i < mysql_num_fields($result);$i++)
{
echo "<th>".mysql_field_name($result,$i).
"</th>";
}
echo " </tr>
</thead>
<tbody>";
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
echo "<tr>";
$row = mysql_fetch_row($result);
for($j = 0;$j<mysql_num_fields($result);$j++)
{
echo("<td>" . $row[$j] . "</td>");
}
echo "</tr>";
}
echo "</tbody>
</table>";
} //end else
echo "
<hr><br>
<form action=\"{$_SERVER['PHP_SELF']}\" method=\"POST\">
<input type='hidden' name='query' value='$query'>
<input type='hidden' name='database'
value={$_POST['database']}>
<input type='submit' name=\"queryButton\"
value=\"New Query\">
<input type='submit' name=\"queryButton\"
value=\"Edit Query\">
</form>";
unset($form);
exit();
} // endif form=yes
/* Section that requests user input of query */
@$query=stripSlashes($_POST['query']);
if (@$_POST['queryButton'] != "Edit Query")
{
$query = " ";
}
?>
<form action="<?php echo $_SERVER['PHP_SELF'] ?>?form=yes"
method="POST">
<table>
<tr>
<td align=right><b>Type in database name</b></td>
<td><input type="text" name="database"
value=<?php echo @$_POST['database'] ?> ></td>
</tr>
<tr>
<td align="right" valign="top">
<b>Type in SQL query</b></td>
<td><textarea name="query" cols="60"
rows="10"><?php echo $query ?></textarea>
</td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit"
value="Submit Query"></td>
</tr>
</table>
</form>
</body></html>
when i'm trying to execute it. such message appears:
"Warning: mysql_connect(): Access denied for user 'ODBC'@'localhost' (using password: NO) in z:\home\localhost\www\2.php on line 11
Warning: mysql_select_db(): Access denied for user 'ODBC'@'localhost' (using password: NO) in z:\home\localhost\www\2.php on line 12
Warning: mysql_select_db(): A link to the server could not be established in z:\home\localhost\www\2.php on line 12
Warning: mysql_query(): Access denied for user 'ODBC'@'localhost' (using password: NO) in z:\home\localhost\www\2.php on line 14
Warning: mysql_query(): A link to the server could not be established in z:\home\localhost\www\2.php on line 14
Database Selected: i"
what does it' mean?
--
Best regards,
Pavel mailto:Kerwant@xxxxxxxxx
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