HI Dan
try this this should work 100%;
echo "<select>";
for ($y=0;$y<=10;$y++) {
$years=date('Y')+$y;
$short_years=date('y')+$y;
printf("<option value=\"%02d\">%d</option>",$short_years,$years);
}
echo "</select>";
On 2/2/07, Dan Shirah <mrsquash2@xxxxxxxxx> wrote:
Hello all,
I am trying to populate a dropdown list to contain the current year to 10
years in the future. Below is the code I'm using:
<?PHP
for ($y=0;$y<=10;$y++) {
$years=date <http://php.net/date>('Y')+$y;
$short_years=date <http://php.net/date>('y')+$y;
echo "$short_years";
echo "<option value=\"$short_years\">$years</option>";
}
?>
I want the selection value to be 2007, 2008, 2009, 2010.... and the
$years
accomplishes this. Howeverm I want the option value to be the two digit
year ex. 07, 08, 09, 10...the $short_years semi accomplishes
this....instead
of getting 07, 08, 08, 10 I get 7, 8, 9, 10...how can I get it to output
the
two year for 07, 08, 09 without it cutting off the zero?
Reagrds,
Dan
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Location: Pune , India
Contact: +91-9890792762
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