jekillen wrote:
Hello php list;
I am having trouble with ereg().
The following is the problem code
$x = ereg("<route name='$to' x='../(.*)/in' rec='.*' />", $get_route, $m);
do we need to break out of the text to include the $to variable??
testing $route I get:
do you mean $get_route?
$route = $m[1]; print $route.'<br>'; jk/in' rec='a_378e6dc4.xml' /> (out put of print)
Is this an example of th input? What does an actual line of $get_route look like? do a var_dump($m); and show output
jk is all I am looking for but is it greed that is missing the forward slash and the single quote? It seems like every time I do this I have to monkey around with it until I get what I want. I have even changed the formatting of files just so a regular expression would work without this sort of trial and error. Is there a way I can turn off greed in php's regex? I am using php v5.1.2 with Apache 1.3.34 Thanks in advance. JK
or better yet, try thisI am assuming on the actual structure of $get_route but the following return to me $match[1] = '../jk'
$to = 'something'; $get_route = "<route name='something' x='../jk/in' rec='998asdf' />";preg_match("|<route name='".$to."' x='(\.\./.*)/in' rec='.*' />|", $get_route, $matches);
var_dump($matches); -- Enjoy, Jim LucasDifferent eyes see different things. Different hearts beat on different strings. But there are times for you and me when all such things agree.
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