Displaying Results on different rows in tables

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Hello all,

I am trying to pull data and then loop through the multiple results display
in seperate rows.
My database contains several tables which are all tied together by the
credit_card_id.  After running the query, it ties the unique record together
by matching the credit_card_id in both tables.  How would I go about
displaying the results of this query in a table with a single row for each
unique record?

Each row of the result will have 5 columns: Request ID, Date/Time Entered,
Status, Payment Type, Last Processed By.

If I assign the results of the query to variables (Such as $id =
$row['credit_card_id'];) how would I display that data?

Would it be something like this:

foreach($row as $data)
{
echo "<table>
       <tr>
        <td><a href=$item->link>$id</a></td>
       </tr>";
 echo "<tr>
        <td>$dateTime</td>
       </tr>
     </table>";
 echo "<tr>          <td>$Status</td>
       </tr>
     </table>";

     }
Below is the code I have so far.

<?php
$database = "database";
$host = "host";
$user = "username";
$pass = "password";
 // Connect to the datbase
 $connection = mssql_connect($host, $user, $pass) or die ('server
connection failed');
 $database = mssql_select_db("$database", $connection) or die ('DB
selection failed');
 // Query the table and load all of the records into an array.
 $sql = "SELECT
    child_support_payment_request.credit_card_id,
  credit_card_payment_request.credit_card_id,
  date_request_received
   FROM child_support_payment_request,
        credit_card_payment_request
     WHERE child_support_payment_request.credit_card_id =
credit_card_payment_request.credit_card_id";
 $result = mssql_query($sql) or die(mssql_error());
 while ($row=mssql_fetch_array($result));
 $id = $row['credit_card_id'];
 $dateTime = $row['date_request_received'];

?>

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