I posted this here as I figured I would need to manipulate this using PHP. The code below doesn't quite work because the date is in the format of 05/05/2006. So I am getting totals for each date, not each year. I need the totals for each year, regardless of the day or month. This is why I figured I'd need to use PHP to maybe put it in an array first or something. Thanks -----Original Message----- From: Joe Wollard [mailto:joe.wollard@xxxxxxxxx] Sent: October 28, 2006 10:30 PM To: Ed Lazor Cc: Beauford; PHP Subject: Re: Query question Agreed, this should go to a MySQL list. But in the spirit of helping I think the following should give you a good starting point. SELECT `year`, COUNT(`year`) AS `count` FROM `tbl` GROUP BY `year` ASC On 10/28/06, Ed Lazor <edlazor@xxxxxxxxx> wrote: > > Use the mysql list :) > > > On Oct 28, 2006, at 3:01 PM, Beauford wrote: > > > Hi, > > > > I have a MySQL database with a date field and a bunch of other > > fields. The date field is in the format - 01/01/2006. What I want to > > do is query the database and create a table that shows just the year > > and how many instances of the year there is. I have been taxing my > > brain for a simple solution, but just not getting it. Any > > suggestions? > > > > Thanks > > > > Example output. > > > > Year Count > > > > 2002 5 > > 2003 8 > > 2004 9 > > 2005 15 > > 2006 22 > > > > ps - I get this information sent to me and I can't change any of the > > data. I just enter it in the db and then hopefully do the query on > > it. > > > > > > -- > PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: > http://www.php.net/unsub.php > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
