Re: <OPTION

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Ron Piggott (PHP) wrote:
I am creating a form right now.  I am using the html SELECT tag.

<SELECT NAME="day_of_month">

The most number of days in a month is 31

I want the output to be <OPTION SELECTED>## based on the value of
$selected_day_of_month variable.  For the days of the month where the
number is not selected the output I am desiring is
<OPTION>1
<OPTION>2
etc.

to be generated through PHP code

I already have a value the user submitted in a variable named
$selected_day_of_month from being stored in a mySQL table

Does anyone know how to do this in a few commands?  I am wanting to
simplify
<?
if ( $selected_day_of_month == "1" ) }
<OPTION SELECTED>1
} ELSE {
<OPTION>1
}

if ( $selected_day_of_month == "2" ) }
<OPTION SELECTED>2
} ELSE {
<OPTION>2
}

?>

etc.

Dang that's painful!! Try this...

<?php
    foreach (range(1, 31) as $day)
    {
        print '<option value="'.$day.'"';
        if ($selected_day_of_month == $day)
            print ' selected';
        print '>'.$day.'</option>';
    }

?>

I added a value to the options (you knew that was missing right?). Obviously you need to output the <select ...> and </select> outside this loop.

-Stut

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