On Wed, 2006-09-06 at 11:03 -0600, Ashley M. Kirchner wrote:
> Robert Cummings wrote:
> > It's because you have written sloppy code and didn't bother to
> > initialize $Dirs to an array. So it's default value is null. You would
> > know this if you had notices enabled.
> >
> Error fixed.
>
> > Also, the other problem is that you are either a) opening the wrong
> > path, b) the path you are opening has no files or directories.
> >
> Neither of those assumptions is correct.
Well then, perhaps you should add some echos so you can see exactly how
your code is executing. I do know for certain that if $Dirs was nul when
passed to sort() that the following never saw the light of day with
respect to processor time:
<?php
$Dirs[$i] = $dh;
?>
While I'm looking at it btw, $i is completely pointless. You should use:
<?php
$Dirs[] = $dh;
?>
Since the index will be automatically incremented by 1 for each entry
added. But hey! Whadda I know?!
>
> > Take note also that your variable is called $Dirs, but readdir() returns
> > all directory contents (including files, links, etc, etc).
> >
> I'm aware of what readdir() returns, and also aware that in my
> particular application, it makes no difference what so ever since there
> are only directories in there. If it also contained individual files, I
> would've named it different. Variable names are exactly that, variable
> names. Whether I called it $Dirs or $Robert_Cummings would make no
> difference what so ever [to me]. But thank you for your opinion.
You're very welcome. I hope you're not writing code for a customer of
some sort. I'd hate to be the one maintaining it after you abandon it...
even if it does have variables named after me (thanks for that). I hope
you initialized $Robert_Cummings btw, I'm not sure I want to be an
implicit null.
Cheers,
Rob.
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