php@xxxxxxxxx wrote:
>
>
> On Wed, 26 Jul 2006 13:22:02 +0200, Jochem Maas <jochem@xxxxxxxxxxxxx> wrote:
>> php@xxxxxxxxx wrote:
>>> Hi
>>> I am reading a username and password from a file. For the moment I am
>> trying to test if the username and password are the same as user inputted
>> username/password.
>>> My code snippet is as follows:
>>> if( $out[0][0] == $u && $out[0][1] == $p ) {
>>
>>
>>> $error = "Login successful!";
>>> }
>>> else {
>>> $error = "Invalid username/password. Try again";
>>> }
>>>
>>> $out[] is an array containing the file data.
>>> $u is the form username and $p the password.
>>> I echo both values once submitted. Even when they match I get invalid
>> username/password message.
>>> If I just test if( $out[0][1] == $u ) it works.
>> take a REALLY GOOD LOOK at your [compound] if statement
>> (hint: what are you checking against $out[0][1]?)
>
> Sorry, that was a typo.
I'm sure it was; and I'm sure that you have lots of typos.
here is test code that proves that if what you say it true regarding
the contents/structure of $out, $u and $p then when the relevant values match you
will get the "Login Successful!" message; seeing as you are not it means you
are testing the wrong variables or something:
// CODE
$out = array(array("user","pwd")); $u = "user"; $p = "pwd";
if($out[0][0] == $u && $out[0][1] == $p) {
echo "Match\n";
} else {
echo "No Match!";
}
// OUTPUT
//Match!
> $out[0][1] is the password. Should have read:
> if( $out[0][1] == $p )
> So that works, once i add the && $out[0][0] == $u
> it no longer works, even though my echo shows both values are the same...
do you know the difference between print_r(), var_dump() and echo?
try:
var_dump($out, $u, $p, (" user " == "user"));
> Thanks again
>
>>> Has anyone any pointers
>> ...
>>
>> simply that array items don't magically swap places in order to
>> do what you mean.
>
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