php@xxxxxxxxx wrote:
if( $out[0][0] == $u && $out[0][1] == $p ) {
$error = "Login successful!";
}
else {
$error = "Invalid username/password. Try again";
}
If I just test if( $out[0][1] == $u ) it works.
If statement above works then $out[0][1] contains user name but in code
snippet
if( $out[0][0] == $u && $out[0][1] == $p ) {
you are testing it against $p which I guess is password..
--
Sameer N. Ingole
weblogic.noroot.org/gallery2/v/travel/lonar/
---
Better to light one candle than to curse the darkness.
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