At 7:21 PM -0500 6/18/06, Rob W. wrote:
>I got the previous question answered, Now here's my next problem.
>
>With the numbers displaying correctly again I got:
>
>1
>2
>3
>4
>5
>6
>7
>10
>11
>12
>13
>14
>15
>16
>17
>18
>19
>20
>21
>22
>25
>
>listed in that order in the database
>
>Now i'm trying to figure out how to write a syntax saying that if like number 8 isnt listed, display it.
>
>I've tried doing a
>
>if ($count != $data) {
> echo "$data";
>}
>$count++;
>
>But when I get to like id number 9 it dont work right because the next entrie is displayed as 10 in the db. So that's my problem is to try and display only them numbers that are not in there. I have also tried putting the numbers in to an array and matching from there but it still come's up as the same as above.
>
>- Rob
Rob:
Why?
If you want to show the number of records in your dB, then just show them. If you want a counter, then add a counter but don't list the id number. Besides, why would you want to anyway?
tedd
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