Here is what I have used for mktime..
$unix_date_33 = mktime(0,0,0,date("m"),date("d")-33,date("Y"));
I am getting the current month, day, and year from the system.
I am subtracting 33 days from the current day.
The result is compared to a date value from the database.
Jef
-----Original Message-----
From: Ryan A [mailto:genphp@xxxxxxxxx]
Sent: Thursday, May 11, 2006 2:38 PM
To: php php
Subject: Mktime formatting problems
Hey,
So far this is what I have done:
-----------------------------
1) read the files from a directory, discard the files
with a .php extention and the directories (eg: . and
.. )
2) put the files into an array ($the_files[])
3) put it into a while loop and display the files like
so:
echo $the_files[$i] . date("F d Y H:i:s.",
filectime($directory_with_files.$the_files[$i]));
-----------------------------
The next step is, I want to only echo the files that
are over x minutes (or x hours) old, ignore anything
below, I am using mktime() along with date() to format
it accordingly...but am unable to do so.
Can someone kindly give me a quick example on how to
do this? sitting too long on the comp, I think i'm
losing it :-(
If you want the php file that i have written please
tell me and will send it to you offlist.
Thanks!
Ryan
------
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