Re: undefined variable

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2006/4/29, Smart Software <info@xxxxxxxxxxxxxxxxxx>:

code below shows all records from products table with an textbox and an
order button for each record

<? $query1 = mysql_query("SELECT * FROM products ");
while ($rowType = mysql_fetch_array($query1))
{ ?>
<table width="500" border="0">
   <tr class="largeheader">
<td width="40%"><?  echo "$rowType[0]"; ?></a> </td>
<td width="10%"><?php  echo "$rowType[1]"; ?></td>
<td width="10%"><input name="quantity" type="text" value="1" size="1"
maxlength="3"></td>
<td width="40%"> <a href="<? echo
"products.php?cat=$cat&toevoegen=1&id=$rowType[7]"; ?>"><img
src="images/bestel1.gif" border="0"></a></td>
</tr>

<?php
}
?>
</table>



if someone presses the button, an item will be ordered.

How can i add the content of the textbox?
i tried this:
<td width="40%"> <a href="<? echo
"products.php?cat=$cat&quantity=$quantity&toevoegen=1&id=$rowType[7]";
?>"><img src="images/bestel1.gif" border="0"></a></td>

but all i get is an error telling me there is a undefined varable


Can you post what the error looks like?

thanx for all help
N. Karademir

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