Re: Re: URL output query

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Rafael wrote:
    Hi Chris,
if the only thing you want is to get the domain (having the whole URL) you have more than one way to solve it. Chris -it's a little akward that Chris answered to Chris- already told you about parse_url(), and since we're talking about strings, I would suggest something like
  $domain = preg_replace('{^([a-z]+://[^/]+).*$}X', '%1', $uri);

Chris wrote:

Greetings PHP folks,

Which PHP function do I use if I want to achieve the following :

http://www.somesite.com/gallery/pics.php is the url...how do I get it to
read only http://www.somesite.com in the browser address bar without the
rest of the directory and filename appearing ?

We are two different people !? Not sure how that's difficult.

I don't know why you'd use a regular expression when you can use a function instead (easier to maintain, it'll be faster, you won't make a mistake)...

But of course there is always more than one way to solve a problem.

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