I believe it is because without the quotes, it is expecting a predefined constant. With the quotes, it is expecting an array key. This is why if you use a word that is not defined as a constant, php will first look for it as a constant, won't find it, then looks through the array treating it like a key. If it is found as a constant, then the constant's value is used as the key. Jason -----Original Message----- From: Chuck Anderson [mailto:hairtwoday@xxxxxxxxx] Sent: Wednesday, February 22, 2006 3:30 PM To: php-general@xxxxxxxxxxxxx Subject: Re: array variables with or without quotes 2dogs wrote: >I recently encountered a situation where I had to retrieve data from a >MYSQL database table with a field named "include". My code looked like this: > >$content_result = mysql_query('SELECT * FROM calander') or >die(mysql_error()); $content_row = mysql_fetch_array($content_result); >if ($content_row[include]) > {go do something;} > >When I tried to run this, PHP treated the word -include- as a control >structure rather than an index name. Understandable. So, I put it in >single quotes ('include') to see what would happen and it works fine. >But I don't understand why! > >What is the difference between $content_row [include] and >$content_row['include']? I have been unable to resolve this question in >the php manual, I need enlightenment. > >2dogs > > http://www.php.net/manual/en/language.types.array.php#language.types.array.f oo-bar -- ***************************** Chuck Anderson . Boulder, CO http://www.CycleTourist.com Integrity is obvious. The lack of it is common. ***************************** -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
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