$currentTS = strtotime("now");
$currentYear = date("Y");
$nextYear = $currentYear + 1;
$lastSundayInSepCurrentYearTS = strtotime("last Sunday",
strtotime("10/1/$currentYear"));
$firstDayNextYearTS = strtotime("1/1/$nextYear");
//
// So your psuedocode becomes...
//
if (($currentTS > $lastSundayInSepCurrentYearTS) &&
($currentTS < $firstDayNextYearTS)) {
$year++;
}
Shaunak Kashyap
Senior Web Developer
WPT Enterprises, Inc.
5700 Wilshire Blvd., Suite 350
Los Angeles, CA 90036
Main: 323.330.9900
www.worldpokertour.com
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-----Original Message-----
From: Jay Paulson [mailto:Jay.Paulson@xxxxxxxxxxxxxx]
Sent: Friday, February 17, 2006 10:07 AM
To: php-general@xxxxxxxxxxxxx
Subject: Last Sunday in September?
Hi,
I'm building a program and I need to find the last Sunday in September
for
every year because the following Monday is the start of a new year for
us.
So 2006 ends on September 24th 2006 and the new year (2007) starts on
September 25th 2006. I was thinking that using the strtotime() would
get me
this information possibly? Is there an easy way to get this
information?
Pseudo code:
If ((date > last Sunday in September this year) &&
(date < Jan 1 of next year)) {
year++
}
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