At 05:39 PM 1/28/2006, Paul Goepfert wrote:
Thanks for the help everyone. I have decided to use javascript to
deal with my second problem. I understand that this is not a
JavaScript fourm but I am having some trouble getting my JS function
to work correctly.
Here is my JS code.
function getEquipment ()
{
var mylist = document.getElementById("equip");
if (mylist.options[mylist.selectedIndex].value=="other")
{
document.writeln("<tr>");
document.writeln(" <td align="left">Other</td>");
document.writeln(" <td><input type="text"
name="other" size="20"></td>");
document.writeln("</tr>");
}
}
This is my code for where the function is called
<select name="equipment" size="1" id="equip" onChange="getEquipment()">
<option value="treadmill">Treadmil</option>
<option value="exercise bike">Exercise
Bike</option>
<option value="other">Other</option>
<option value="rowing machine"
selected>Rowing Machine</option>
</select>
My problem is when the page loads in a web browser the Option "Other"
is selected every time. From what you can see from my code "Rowing
machine is the one that I want to be shown when the page loads.
Anyway can anyonne tell me why my code is not executing correctly. I
am not too familiar with java script. What I am trying to accomplish
is if Other is selected then add a new table row below the drop down
menu with the content that I have in the function.
If no one can help with this would someone please direct me to a Java
Script Forum.
Thanks
Paul
Javascript@xxxxxxxxxx
Registration is required.
MT
--
No virus found in this outgoing message.
Checked by AVG Anti-Virus.
Version: 7.1.375 / Virus Database: 267.14.23/243 - Release Date: 1/27/2006
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php