$sql = "SELECT nameOfPedigree FROM tbpedigrees WHERE nameOfPedigree like '\'%' "; Maybe this could work... -- "El único error real es aquel en el que no hemos aprendido nada."
$sql = "SELECT nameOfPedigree FROM tbpedigrees WHERE nameOfPedigree like '\'%' "; Maybe this could work... -- "El único error real es aquel en el que no hemos aprendido nada."