Re: how to exist within the context?

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Hi,

Try this:

<?php
$submit = $_POST['submit'];
$name = $_POST['yourname'];

if ($submit)
{
   do {
       if ($name=="")
       {
         print "Please enter your name!";
         break;
       }
   } while (0);
}
echo "Continue processing...";
?>

It's a hack, but it works.

Cheers,

David Grant

Bing Du wrote:
> Hi,
> 
> One webpage has its banner, left menu and footer ect that are controled
> by the template.  I want this php script to output the form and
> processing result within the page structure.  Without exit, if the
> 'yourname' field is empty, the script would output 'Please enter your
> name!' fine within the page structure (that is, banner, menu and footer
> are all there).  But obviously the script does not terminate as it's
> supposed to.  With exit, the script terminates fine, but it outputs the
> result in a page without banner, menu and footer.  So what's the correct
> way to get the script stop and output its results always in the page
> structure.
> 
> <form method=post>
> <input name="yourname" type="text" size="20">
> <input name="submit" type="submit" value="submit">
> </form>
> 
> <?php
> 
> $submit = $_POST['submit'];
> $name = $_POST['yourname'];
> 
> if ($submit)
> {
>    if ($name=="")
>   {
>     print "Please enter your name!";
>     //exit;
>   }
> }
> 
> echo "Continue processing...";
> ?>
> 
> Thanks in advance,
> 
> Bing
> 

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