On 21 Nov 2005, at 09:26, Georgi Ivanov wrote:
AFAIK, in PHP5 one can't call function with function parameters .
The error is that you only can pass variables by reference.
foo(strlen('aaa'),strlen('bbbb'));
You can call functions like that without problems UNLESS the function
is expecting values by reference, i.e. results are passed back
through the parameters. If you supply a function result, then you may
as well not be calling the function as you'll never be able to get a
result back from it, hence the error message. e.g.
function foo(&$a, $b) {
$a = $a.$b;
}
If you call this as you asked, where would the result go?
Is there some sort of workaround ?
As was suggested, put your values in variables before calling the
function, though the code example you posted suggests you're trying
to do something odd.
Marcus
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Marcus Bointon
Synchromedia Limited: Putting you in the picture
marcus@xxxxxxxxxxxxxxxxxx | http://www.synchromedia.co.uk
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