On Tue, 2005-09-20 at 19:20, adriano ghezzi wrote:
> hy guys this night I'm quite tired
>
> I need a little tip
>
> ok var n could be from 0 to 12
>
> var f must be set
> f=1 if 0<n<=4
> f=2 if 5<n<=7
> f=3 if 8<n<=12
> f=4 if n>12
>
> due to my fatigue I coded four if-if else statement,
>
> in other languages it is possible use conditional epression in switch case
> like
> switch $n
>
> case (0<n<=4):
> ........
>
> but no in php
>
> any suggestion for more professional coding then 4 if/else statement
For such a small set I'd say that's as good as it gets. However if there
were 100 intervals you could try the following:
function f( $n )
{
$map = array
(
// min, max, f
array( 0, 4, 1 ),
array( 5, 7, 2 ),
array( 8, 12, 3 ),
array( 17, null, 4 ),
);
foreach( $map as $criteria )
{
if( $criteria[0] === null || $n > $criteria[0]
&&
$criteria[1] === null || $n <= $criteria[1] )
{
return $criteria[2];
}
}
return null;
}
I think your code is flawed by the way, the lower endpoints are only
compared for greater than value and not equal to value meaning $n with
value 4 would not match any f value.
Cheers,
Rob.
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