On Jul 6, 2005, at 2:07 PM, Ryan A wrote:
Hi,
I'm confused, this should give me the age as 17 instead of 16...but it
does
not...any ideas why?
<?php print date("Y:m:d");
$age="1988-07-06";
$day1=strtotime($age);
$day2 = strtotime(date("Y-m-d"));
$dif_s = ($day2-$day1);
$dif_d = ($dif_s/60/60/24);
$age = floor(($dif_d/365.24));
echo $age;
?>
Thanks,
Ryan
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If I change $day2 to =time(); instead of strtotime() I get 17. Could be
some weirdness going on with using date()?.
Edward Vermillion
evermillion@xxxxxxxxxxxx
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