x years old

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Hey guys,
This is the code I am using to display a persons age from the mysql db:

$day1=strtotime($age);
$day2 = strtotime(date("Y-m-d"));
$dif_s = ($day2-$day1);
$dif_d = ($dif_s/60/60/24);
$age = round(($dif_d/365.24));

but when someone entered their birth day($age) as 1988-07-06 it is showing
it as
17 years old instead of 16...any idea whats wrong in the above code?

Thanks,
Ryan

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