Robert Cummings wrote:
...
There's a difference between a reference to a reference and a copy of a
reference *hehehe*.
Cheers,
Rob.
Dear diary: jackpot!
Now that makes sense. And am I correctly filling in the blanks when I
guess that $foo3 = $aObj is merely copying the reference instead of
referencing the reference? I probably could have written that more
clearly, but I think you get what I'm saying.
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