btw! saying:
add($a=null,$b=null,$c=null)
is as good as saying:
add($a,$b,$c)
No, it's not. Because in this case $a, $b and $c are all uninitialized variables and (if this is a function definition) then you *have* to supply $a $b and $c parameters.
Even if you were just calling add() this wouldn't be wise. Consider the possibility that your server uses register_globals. In that case I can browse to:
http://yoursite.com/yourpage.php?a=25&b=20&c=1234567890
Not to mention the code injection possibilities.
thanks, vedanta
On 4/28/05, Vedanta Barooah <vedanta.barooah@xxxxxxxxx> wrote:
Well that was simple, but this is what i am trying to solve:
if you refer to the php documentation for ldap_open() function it says:
resource ldap_search ( resource link_identifier, string base_dn, string filter [, array attributes [, int attrsonly [, int sizelimit [, int timelimit [, int deref]]]]])
if you look at the 4th and the 6th arguments to the function attributes is an array while sizelimit is an int, i want to pass the sixth element without passing the 4th and the 5th ... how do i do that??
i tried these options:
# this does not work, $rs=ldap_search($con,"o=vodoo.com","(objectClass*)",array(),0,500);
$rs = ldap_search($con, "o=vodoo.com", "(objectClass*)", null, null, 500);
# this wont works :(( $rs=ldap_search($con,"o=vodoo.com","(objectClass*)",' ',0,500);
# this also goofs! $rs=ldap_search($con,"o=vodoo.com","(objectClass*)",NULL,0,500);
here that 5th arg works if i pass a zero as ... 0 means the default behaviour!!
any ideas ... clues ?
Thanks, Vedanta Barooah
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