function add ($a=1, $b=2, $c=3) {
return $a + $b + $c;
}
add(1, null, 1);
will do just fine
r.,
Bostjan
On Thursday 28 April 2005 14:16, Marek Kilimajer wrote:
> Vedanta Barooah wrote:
> > Hello All,
> > Cosider this :
> >
> > function add($a=1,$b=2,$c=3){
> > return $a + $b + $c;
> > }
> >
> > how do i skip the second argument while calling the function, is there
> > a process like this:
> >
> > echo add(1,,1); # where i expect 2 to be printed,
>
> php does not support this. you can workaround this using:
>
> function add($a = null,$b = null, $c = null){
> if(is_null($a)) $a = 1;
> if(is_null($b)) $b = 2;
> if(is_null($c)) $c = 3;
> return $a + $b + $c;
> }
>
> add(1, null, 1);
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