Jochem Maas wrote:
Marek Kilimajer wrote:
Jochem Maas wrote:
John Nichel wrote:
Jochem Maas wrote:
AndreaD wrote:
I have a session variable called
$_SESSION['total'] the problem is I can't delete/reset it. I have
tried
$_SESSION['total']= 0;
$_SESSION['total']= "";
I guess you didn't know/think of trying null:
$_SESSION['total'] = null;
...which has the same effect as using:
unset($_SESSION['total']); // as you have been told on at least 3
diff occasions ;-)
Not true. If you set it to null, it still exists...it's just null.
If you unset it, the variable no longer exists.
fair enough, but then how do you differentiate between a var that
exists and is null
and a non-existant var?
Marek pointed out that setting error reporting to E_ALL, shows a notice
when you var_dump() the unset() var and not the null var, but other
than that
the unset() var and the null var give the same result from isset()
and empty()
e.g:
error_reporting(E_ALL);
$X = array("total" => 1);
$X["total"] = null;
if ( isset ( $X["total"] ) ) {
echo ( "Yes" );
} else {
echo ( "No" );
}
var_dump( $X["total"] );
unset ( $X["total"] );
if ( isset ( $X["total"] ) ) {
echo ( "Yes" );
} else {
echo ( "No" );
}
var_dump( $X["total"] );
which produces the following for me:
NoNULL
NoPHP Notice: Undefined index: total in Command line code on line 23
NULL
so that means you would have to set a suitable error handler for
E_NOTICE just before
the place you want to check if the var exists and unset it
immediately afterwards??
No, use isset() or empty() to check if the variable exists and you
won't get notices
right, I'm thinking about it too much - getting confused for no reason :-).
but that still leaves the point that you can't tell the difference
between a
null var and one that is not set at all - this seems odd if there is
actually
a difference (okay so you can tell the difference but it seems to
require that
you generate an E_NOTICE which is not the idea really is it).
You can use get_defined_vars() and array_key_exists() if you really need to.
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