OK got that. Thanks...
"Jason Petersen" <fuzzybad@xxxxxxxxx> kirjoitti
viestissä:5eafe1ec0503020806886216f@xxxxxxxxxxxxxxxxx
> On Wed, 2 Mar 2005 13:02:39 +0200, William Stokes <kalles@xxxxxxxxxxxxx>
> wrote:
>> Hello
>>
>> Can someone explain this to me. I don't know how to read this.
>>
>> if (!$variable = mysql_query("select id,sessid from users where ...
>>
>> What is this "if(!"
>
> This is a way to run a SQL query, capture the return value, and
> perform an action if the query failed. For code readability, I would
> probably write that as two statements:
>
> $variable = mysql_query("SELECT * FROM blah");
> if(!$variable) { error_handler(mysql_error()); }
>
> See the documentation for information on mysql_query return values:
> http://us2.php.net/manual/en/function.mysql-query.php
>
> Jason
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