OK got that. Thanks... "Jason Petersen" <fuzzybad@xxxxxxxxx> kirjoitti viestissä:5eafe1ec0503020806886216f@xxxxxxxxxxxxxxxxx > On Wed, 2 Mar 2005 13:02:39 +0200, William Stokes <kalles@xxxxxxxxxxxxx> > wrote: >> Hello >> >> Can someone explain this to me. I don't know how to read this. >> >> if (!$variable = mysql_query("select id,sessid from users where ... >> >> What is this "if(!" > > This is a way to run a SQL query, capture the return value, and > perform an action if the query failed. For code readability, I would > probably write that as two statements: > > $variable = mysql_query("SELECT * FROM blah"); > if(!$variable) { error_handler(mysql_error()); } > > See the documentation for information on mysql_query return values: > http://us2.php.net/manual/en/function.mysql-query.php > > Jason -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php