Greetings! If I do the following, it gives me a blank page. However, instead of using the variable, if I put in $id_num = "191" Then it will display the information. Does anyone know what I am doing wrong? I hope you understand my question... Thank you in advance! Here is the link I use to this page: <a href="view_prayer.php?id_num=191">view</a> --------------------------------------------------------------------------- <? // log into our local server using the MySQL root user. $dbh = mysql_connect( "localhost", "username", "password" ); // select the database. mysql_select_db( "prayer" ) or die ( mysql_error() . "\n" ); $prayer = $_POST["prayer"]; $id_num = $_POST["id_num"]; //and read it back for printing purposes. $get_table_data = "SELECT * FROM prayer WHERE id_num= \"$id_num\""; $response = mysql_query( $get_table_data, $dbh ); //now print it out for the user. if ( $one_line_of_data = mysql_fetch_array( $response ) ) { extract ( $one_line_of_data ); } ?> <html> <head> <title>Prayer for <? echo "$date\n"; ?></title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> </head> <body> <?PHP $prayer = nl2br ($prayer); $prayer = stripslashes ($prayer); echo "$prayer\n"; ?> </body> </html> --------------------------------------------------------------------------- -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php