----- Original Message -----
From: "Wil" <wil.hitchman@xxxxxxxxxxxx>
To: <php-general@xxxxxxxxxxxxx>
Sent: Thursday, January 06, 2005 9:35 PM
Subject: Php error with MySql
> I get the following error
>
> Warning: mysql_num_rows(): supplied argument is not a valid MySQL result
> resource in /home/wilmail/public_html/elblog.php on line 7
> &n=& //error ends here
>
> with the following bit of code
>
> $qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC");
>
Try " echo mysql_error() " just after your query. It's rather common to
make typos or forget to select DB.
> $nRows = mysql_num_rows($qResult);
> $rString ="&n=".$nRows;
>
> If I am just naming a variable how is the argument not valid?
>
> Thanks,
>
> Wil
>
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