[snip] I get the following error Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/wilmail/public_html/elblog.php on line 7 &n=& //error ends here with the following bit of code $qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC"); $nRows = mysql_num_rows($qResult); $rString ="&n=".$nRows; If I am just naming a variable how is the argument not valid? [/snip] Perhaps your query failed, but you've got no error checking. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php