On Tuesday 28 December 2004 23:43, GH wrote:
> During the code... it gets to the following point...
>
> [snip]
> #############################################
> # Check if report report is present or not #
> #############################################
> if(!mysql_num_rows($dba['results']['attendance_report'])){
> #report is not present
> return 0;
> }
> else {
> #report is present
> return 1;
> #gets here
> }
> [/snip]
>
> it gets to the return 1 section....
Just to be sure, how are you determining that your code does indeed goes to
the 'else' branch and return 1? Because if it does indeed return 1 then:
echo isAttendanceReport(1); // should display 1
For debugging something like this I would put in echo statements (or
trigger_error()) all over the place to indicate which part of the code is
being executed.
> however the calling statement just does not seem to work....
If isAttendanceReport() did indeed return 1 then the if-clause in
displayMenu() would be obviously be true and would obviously execute (unless
you have uncovered a bug in PHP). So the most likely explanation is that
isAttendanceReport() is NOT returning 1.
> using SID = 1, mysql_num_rows($dba['results']['attendance_report'])
> evaluates to 8
>
> Dunno if that helps....
How does $dba['results']['attendance_report'] get assigned? What variables
does it rely on? What variables are present/not present in the case that
succeeds/fails?
> > Isolate the problem, just run isAttendanceReport() on its own and plugin
> > various values to see what comes back.
>
> How can I do that... I have tried but how do you see what the output
> is? I have tried just echo ing it, print_r, var_dump ...
By not running unnecessary code. In this case you seemed to have determined
that isAttendanceReport() is not returning what you think it should be
returning. Hence running displayMenu() to test for the return value of
isAttendanceReport() is unnecessary, particularly when the execution of
displayMenu() is itself subject to a switch construct. So cut through the
crap and just run isAttendanceReport() direct as in:
echo isAttendanceReport(SOME_VALUE_FOR_SID);
If you still don't get any joy then dig deeper. What isAttendanceReport()
returns is solely dependent on:
mysql_num_rows($dba['results']['attendance_report'])
As I have hinted above you have to find out what code is setting
$dba['results']['attendance_report'], what factors (variables) will affect
that code, and even try running that bit of code direct instead of going
through isAttendanceReport() (which itself is adding another layer of
unnecessary complexity).
--
Jason Wong -> Gremlins Associates -> www.gremlins.biz
Open Source Software Systems Integrators
* Web Design & Hosting * Internet & Intranet Applications Development *
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