RE: grabbing source of a URL

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Oops missed part of your question;

> know what function to use to grab the page.  for the string 

http://us2.php.net/manual/en/function.fopen.php

There are some good samples on the page

       $dh = fopen("$url",'r'); 
       $result = fread($dh,8192);                                    

Hope this is what you need.

Warren Vail


> -----Original Message-----
> From: Adam Williams [mailto:awilliam@xxxxxxxxxxxxxxxx] 
> Sent: Friday, December 10, 2004 9:56 AM
> To: php-general@xxxxxxxxxxxxx
> Subject:  grabbing source of a URL
> 
> 
> Hi, I don't know what functions to use so maybe someone can 
> help me out.  
> I want to grab a URL's source (all the code from a link) and 
> then cut out 
> a block of text from it, throw it away, and then show the page.
> 
> For example, if I have page.html with 3 lines:
> 
> <html><head><title>hi</title></head>
> <body>
> <!-- line a -->
> this is line a
> <!-- end line a -->
> <!-- line b -->
> this is line b
> <!-- end line b -->
> <!-- line c -->
> this is line c
> <!-- end line c -->
> </body></html>
> 
> i want my php script to grab the source of page.html, strip out:
> 
> <!-- line a -->
> this is line a
> <!-- end line a -->
> 
> and then display what is left, how would I go about doing 
> this?  I don't 
> know what function to use to grab the page.  for the string 
> to remove, I 
> know I can probably do a str_replace and replace the known code with 
> nothing.
> 
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