I suspect that you don't really want to cut out everything but the text (since you plan to display it) but check out; http://us2.php.net/manual/en/function.strip-tags.php Now, keep in mind that since you are getting the source from the url, and I'm guessing that the web server serving up the source will process php files, this function will probably never see any php in that case, so when you said "a URL's source" you must have meant "html source" generated by a php program. Warren Vail > -----Original Message----- > From: Adam Williams [mailto:awilliam@xxxxxxxxxxxxxxxx] > Sent: Friday, December 10, 2004 9:56 AM > To: php-general@xxxxxxxxxxxxx > Subject: grabbing source of a URL > > > Hi, I don't know what functions to use so maybe someone can > help me out. > I want to grab a URL's source (all the code from a link) and > then cut out > a block of text from it, throw it away, and then show the page. > > For example, if I have page.html with 3 lines: > > <html><head><title>hi</title></head> > <body> > <!-- line a --> > this is line a > <!-- end line a --> > <!-- line b --> > this is line b > <!-- end line b --> > <!-- line c --> > this is line c > <!-- end line c --> > </body></html> > > i want my php script to grab the source of page.html, strip out: > > <!-- line a --> > this is line a > <!-- end line a --> > > and then display what is left, how would I go about doing > this? I don't > know what function to use to grab the page. for the string > to remove, I > know I can probably do a str_replace and replace the known code with > nothing. > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
