On Thu, 2004-12-09 at 13:41 -0500, John Nichel wrote:
> Danny Brow wrote:
> > Below is a snip of a program I am writing, I am a little new to php.
> > Any how, I can't for the life me figure out why one of my functions
> > cannot grab the item_pics1 variable. I have tried passing the variable
> > to the function, tried using $GLOBALS['item_pic1']. So I guess my
> > question is, does PHP in some cases need to have a variable in a if
> > statement sent back to the global scope? everything works but the
> > str_replace item_pics1. Hope this is enough code.
> <snip>
>
> If you want to use a variable from outside the function, you either have
> to pass it to the function; if you want to change it, you have to pass
> it by reference, or make it global inside the function....
>
> function foo ( $bar ) {
> /--code--/
> }
>
> function foo ( &$bar ) {
> /--code--/
> }
>
> function foo() {
> global $var;
> /--more code--/
> }
>
See this is where the confusion is, I've tried all these and it still
does not work. I'm going to read the whole page on variable scope a few
times, see if I missed something. Maybe it's something else in my code
screwing my up.
Thanks.
Dan.
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