Below is a snip of a program I am writing, I am a little new to php. Any how, I can't for the life me figure out why one of my functions cannot grab the item_pics1 variable. I have tried passing the variable to the function, tried using $GLOBALS['item_pic1']. So I guess my question is, does PHP in some cases need to have a variable in a if statement sent back to the global scope? everything works but the str_replace item_pics1. Hope this is enough code.
<snip>
If you want to use a variable from outside the function, you either have to pass it to the function; if you want to change it, you have to pass it by reference, or make it global inside the function....
function foo ( $bar ) {
/--code--/
}function foo ( &$bar ) {
/--code--/
}function foo() {
global $var;
/--more code--/
}I may be mistaken, but I think the $GLOBALS array was introduced in 4.3.0.
http://us4.php.net/manual/en/language.variables.scope.php
-- John C. Nichel ÜberGeek KegWorks.com 716.856.9675 john@xxxxxxxxxxxx
-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
