Re: Problem with parameter count in strstr()

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* Shaun <shaunthornburgh@xxxxxxxxxxx>:
> I am trying to ensure that all data added to each element of $my_data_array 
> has no commas, however I get an error message saying Warning: Wrong 
> parameter count for strstr()
>
> $my_data_array[] =
>           strstr( $data[1], ",", " " );
>           strstr( $data[2], ",", " " ).', '.
>           strstr( $data[3], ",", " " ).', '.
>           strstr( $data[6], ",", " " ).', '.
>           strstr( $data[13], ",", " " ).', '.
>           strstr( $data[14], ",", " " ).', '.
>           strstr( $data[15], ",", " " ).', '.
>           strstr( $data[16], ",", " " ).', '.
>           strstr( $data[17], ",", " " ).', '.
>           strstr( $data[18], ",", " " ).', '.
>           strstr( $data[19], ",", " " ).', '.
>
> Could someone tell me what I am doing wrong here please?

A couple things:

* Syntax for strstr() is strstr(string $haystack, string $needle) --
  you're passing it three arguments instead of two

* What exactly are you concatenating, and where do you expect it to go?
  If you're trying to create a joined list of $data elements 1-19 and
  assign it to a variable, you're going to run into issues when you get
  to that semicolon at the end of your second line ;-)

Also, if you're simply trying to do the following:

    * Join a list of elements with a , 
      * but only join the part of the element preceding a comma (or
        space? not sure of your intentions as you've got bad arguments)

Then you may want to try the following:

    function subStr($n)
    {
        return strstr($n, ',');
    }

    $stripped = array_map('subStr', $data);
    $my_data_array[] = join(', ', $stripped);


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Matthew Weier O'Phinney           | mailto:matthew@xxxxxxxxxx
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