Re: Add methods to object dinamically

[Greg Beaver <cellog@xxxxxxx>]

Francisco M. Marzoa Alonso wrote:
> I've seen that's possible to add members to objects dinamically, in 
> example:
>
> class MyClass {
>    private $a;
> }
>
> $MyObject = new MyClass ();
> $MyObject->b = 1;
>
> Now $MyObject has a public member called 'b' that has a value of '1'.
>
> The question is, is it possible to add methods in the same way?
>
> I meant something such as:
>
> function sum ( $this ) {
>    return $this->a+$this->b;
> }
>
> $MyObject->sum = sum;
>
> Note that code will not work, but it illustrates what I'm asking for.

Sort of :)

In PHP5, this will work.

<?php
class DoesStuff
{
    private $_methods = array();
    public function __call($method, $params)
    {
        if (isset($this->_methods[$method])) {
            $call = $this->_methods[$method];
            return $call($this);
        }
    }

    public function __set($var, $value)
    {
        if (is_string($value) && is_callable($value)) {
            $this->_methods[$var] = $value;
        } else {
            $this->$var = $value;
        }
    }
}

function test($o)
{
    return $o->val;
}
$o = new DoesStuff;
$o->val = 4;
$o->test = 'test';
echo $o->test();
?>

However, you won't have access to private or protected data members.  It 
is always better to rigidly define your methods, and extend the class as 
someone else suggested.

Greg

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