In that case, you could do this:
$x = 1;
$query = mysql_query("select name from names order by date desc");
while($result = mysql_fetch_array($query))
{
$all_names[$x] = $result['name'];
$x++;
}
-TG
> -----Original Message-----
> From: Afan Pasalic [mailto:afan@xxxxxxxx]
> Sent: Monday, October 18, 2004 2:33 PM
> Cc: php-general@xxxxxxxxxxxxx
> Subject: Re: setting index of array as 1
>
>
> It's not what I was looking for. Looks like I didn't explain
> very well :)
>
> look at this case:
>
> $query = mysql_query("select name from names order by date desc");
> while($result = mysql_fetch_array($query))
> {
> $all_names[] = $result['name'];
> }
>
> in this case the array $all_names starts with index 0.
>
> I can't put
>
> $all_names[1] = $result['name'];
>
> because every next entry will get index 1 and overwrite old
> one and on
> the end I'll have an array of just one element :)
>
> -afan
>
>
> Matthew Sims wrote:
> >>when create an array using:
> >>$new_array[] = 'something';
> >>first index of new array is 0
> >>
> >>how can I though set that first index is 1 - except
> "reorganize" array
> >>after is created?
> >>
> >>thanks
> >>
> >>-afan
> >
> >
> > $new_array = array(1 => 'first','second','third');
> >
> > echo $new_array[1]; <--- Will echo first
> >
>
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