for ($i=0; $i<count($all_names); $i++)
{
$new_array[$i+1] = $all_names[$i];
}
// just writting to a new array and incrememnting the subscript by 1
-B
----- Original Message -----
From: Afan Pasalic <afan@xxxxxxxx>
Date: Monday, October 18, 2004 2:33 pm
Subject: Re: setting index of array as 1
> It's not what I was looking for. Looks like I didn't explain very
> well :)
>
> look at this case:
>
> $query = mysql_query("select name from names order by date desc");
> while($result = mysql_fetch_array($query))
> {
> $all_names[] = $result['name'];
> }
>
> in this case the array $all_names starts with index 0.
>
> I can't put
>
> $all_names[1] = $result['name'];
>
> because every next entry will get index 1 and overwrite old one
> and on
> the end I'll have an array of just one element :)
>
> -afan
>
>
> Matthew Sims wrote:
> >>when create an array using:
> >>$new_array[] = 'something';
> >>first index of new array is 0
> >>
> >>how can I though set that first index is 1 - except "reorganize"
> array>>after is created?
> >>
> >>thanks
> >>
> >>-afan
> >
> >
> > $new_array = array(1 => 'first','second','third');
> >
> > echo $new_array[1]; <--- Will echo first
> >
>
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