Re: forms

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Thanks-- i got that going-GREAT !  now i have a form that creates the
database and tables, any ideas how i can get this info to change the
connect_db file so that it doesnt have to be done manually.



"Minuk Choi" <Choi.Minuk@xxxxxxxxxxx> wrote in message
news:000401c4af3f$858bf940$0200a8c0@xxxxxxxx
> try this :
>
> $link = mysql_connect($host, $user, $pass);
>
> Note : No SINGLE quotes.
>
> In PHP, quotations are as follows
>
> $host = 'localhost';
> $a = '$host';
> $b = "$host";
>
> echo $a;
>
> that prints $host
>
> echo $b;
>
> that prints localhost.
>
> HTH
> -Minuk
>
>
> ----- Original Message -----
> From: "bigmark" <neretlis@xxxxxxxxxxxxxx>
> To: <php-general@xxxxxxxxxxxxx>
> Sent: Sunday, October 10, 2004 10:23 PM
> Subject:  forms/variables/create database
>
>
> > hi, does anyone know why this is not working, i have married 2 pieces of
> > code together and i have no idea what im doing--any help is appreciated.
> > I get an error that says it cant find the host--$host so obviusly its
not
> > passing it from the form.
> >
> > /////////////////////////////////////////
> > <?php
> > $host =  $_POST['host'];
> > $user =  $_POST['user'];
> > $pass =  $_POST['pass'];
> > $db_name =  $_POST['db-name'];
> >
> >
> > $link = mysql_connect('$host', '$user', '$pass');
> > if (!$link) {
> >   die('Could not connect: ' . mysql_error());
> > }
> >
> > if (mysql_create_db('db_name')) {
> >   echo "Database created successfully\n";
> > } else {
> >   echo 'Error creating database: ' . mysql_error() . "\n";
> > }
> > ?>
> > /////////////////////////////////////////////
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >

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