Re: forms/variables/create database

"Minuk Choi" <Choi.Minuk@xxxxxxxxxxx> · Sun, 10 Oct 2004 23:08:02 -0400

try this : 

$link = mysql_connect($host, $user, $pass);

Note : No SINGLE quotes.

In PHP, quotations are as follows 

$host = 'localhost';
$a = '$host';
$b = "$host";

echo $a;

that prints $host

echo $b;

that prints localhost.

HTH
-Minuk

----- Original Message ----- 
From: "bigmark" <neretlis@xxxxxxxxxxxxxx>

To: <php-general@xxxxxxxxxxxxx>

Sent: Sunday, October 10, 2004 10:23 PM

Subject:  forms/variables/create database

hi, does anyone know why this is not working, i have married 2 pieces of
code together and i have no idea what im doing--any help is appreciated.
I get an error that says it cant find the host--$host so obviusly its not
passing it from the form.

/////////////////////////////////////////
<?php
$host =  $_POST['host'];
$user =  $_POST['user'];
$pass =  $_POST['pass'];
$db_name =  $_POST['db-name'];

$link = mysql_connect('$host', '$user', '$pass');
if (!$link) {
  die('Could not connect: ' . mysql_error());
}

if (mysql_create_db('db_name')) {
  echo "Database created successfully\n";
} else {
  echo 'Error creating database: ' . mysql_error() . "\n";
}
?>
/////////////////////////////////////////////

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