Re: Minimizing pinhole image falloff

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The intensity pattern of diffraction (function of theta) from a point source
through a round aperture is the square of a 1st order Bessel function of the
first kind of a function of theta & lamda, all divided by the same function
of theta & lamda.

~ [pi * r^2 * J(f(theta, lamda)) / f(theta, lamda)]^2

where:
    J(x) is the 1st order Bessel function of the first kind of x, and
    f(theta, lamda) = 2 * pi * r * sin(theta) / lamda, and
    r is the radius of the aperture, and
    lamda is the wavelength.

This function looks very much like the old familiar sin(x) / x pattern,
squared.

Regards,
Bob...
--------------------------------------------
"Do not suppose that abuses are eliminated by destroying
the object which is abused.  Men can go wrong with wine
and women.  Shall we then prohibit and abolish women?"
-Martin Luther

From: "Chris" nimbo@ukonline.co.uk


> There will also be a diffraction effect because of the difference of path
> length across the pinhole and the wavelength of light.  I can't remember
the
> answer but you have to integrate the light arriving at a point from across
> the pinhole and it makes a difference as it is circular. I will try to do
> the integration shortly but if I remember correctly there is a term
> (theta)/sin(theta) in it somewhere.
>


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