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Re: subquery/alias question

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Michael Glaesemann wrote:

On Sep 25, 2007, at 17:30 , Alvaro Herrera wrote:

Michael Glaesemann wrote:

select dom_id,
       dom_name,
       usr_count
  from domains
  natural join (select usr_dom_id as dom_id,
                       count(usr_dom_id) as usr_count
                  from users) u
  where usr_count > 0
  order by dom_name;

Maybe the usr_count should be tested in a HAVING clause instead of
WHERE?  And put the count(*) in the result list instead of a subselect.
That feels more natural to me anyway.

I believe you'd have to write it like

select dom_id, dom_name, count(usr_dom_id) as usr_count
  from domains
  join users on (usr_dom_id = dom_id)
  having count(usr_dom_id) > 0
  order by dom_name;

I don't know how the performance would compare. I think the backend is smart enough to know it doesn't need to perform two seq scans to calculate count(usr_dom_id), but I wasn't sure.

Madison, how do the two queries compare with explain analyze?

Thanks for your reply!

  Unfortunately, in both cases I get the error:

nmc=> SELECT dom_id, dom_name, COUNT(usr_dom_id) AS usr_count FROM domains JOIN users ON (usr_dom_id=dom_id) HAVING COUNT (usr_dom_id) > 0 ORDER BY dom_name;
ERROR:  syntax error at or near "COUNT" at character 25
LINE 1: SELECT dom_id, dom_name COUNT(usr_dom_id) AS usr_count FROM ...

  I've been struggling with some deadlines, so for now I'm using just:

SELECT d.dom_id, d.dom_name FROM domains d WHERE (SELECT COUNT(*) FROM users u WHERE u.usr_dom_id=d.dom_id) > 0 ORDER BY d.dom_name ASC;

Which gives me just the domains with at least one user under them, but not the count. This is not ideal, and I will have to come back to it next week. In the meantime, any idea what the GROUP BY error is? If not, I'll read through the docs on 'GROUP'ing once I get this deadline out of the way.

Thank you all for your help! I am sure I will have more question(s) next week as soon as I can get back to this.

Madi

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