On 6/7/21 3:12 PM, David Gauthier wrote:
Hi:
I suspect I'm not the first to ask about this but couldn't find anything
after googling for a bit. So here goes....
I'd like to get the "age" difference between two times which span either
all or part of a weekend but exclude any time that transpired during the
weekend.
Example (please pardon the non-timestamp vals here...)
age('Monday-Noon','Prev-Friday-Noon')
would give me '1 day'.
...and...
age('Sunday-Noon','Prev-Friday-Noon')
would give me '12 hours'
You get the picture.
Has this wheel already been invented ?
I don't see an easy way to do this off-hand.
All Ears :-)
Perhaps not the prettiest of solutions, but what about something like this?
8<----------------------------------------
CREATE OR REPLACE FUNCTION nonweekendhours(startts timestamptz, endts
timestamptz)
RETURNS interval AS $$
SELECT
(SUM(case when extract(dow from g.ts) > 0
and extract(dow from g.ts) < 6 then
1
else
0 end) || ' hours')::interval
FROM generate_series(startts, endts - '1 hour'::interval,'1 hour') AS
g(ts)
$$ LANGUAGE sql;
SELECT nonweekendhours('2021-06-04 12:00:00','2021-06-06 12:00:00');
nonweekendhours
-----------------
12:00:00
(1 row)
SELECT nonweekendhours('2021-06-04 12:00:00','2021-06-07 12:00:00');
nonweekendhours
-----------------
24:00:00
(1 row)
SELECT nonweekendhours('2021-06-04 12:00:00','2021-06-11 12:00:00');
nonweekendhours
-----------------
120:00:00
(1 row)
8<----------------------------------------
HTH,
Joe
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