Re: How to create function returning numeric from string containing percent character

[Ben Madin <ben@xxxxxxxxxxxxx>]

I suspect it will depend on your localisation whether you need to account for different decimal separators, but just in case:

SELECT replace(substring('-1,2%' from '^-?\d*[.,]?\d*'), ',', '.')::numeric;

On Wed, 22 Jul 2020 at 18:50, Andrus <kobruleht2@xxxxxx> wrote:

val function should return numeric value from string up to first non-digit character, considering first decimal point also:

    val('1,2TEST')  should return 1.2
    val('1,2,3')  should return 1.2
    val('-1,2,3')  should return -1.2

I tried

    CREATE OR REPLACE FUNCTION public.VAL(value text)
      RETURNS numeric AS
    $BODY$
    SELECT coalesce(nullif('0'||substring(Translate($1,',','.'), '^-?[0-9]+\.?[0-9]*$'),''),'0')::numeric;
    $BODY$ language sql immutable;

but if string contains % character,

    select val('1,2%')

returns 0.

How to force it to return 1.2 ?

It should work starting from Postgres 9.0

Posted also in

https://stackoverflow.com/questions/63032072/how-to-create-function-returning-value-up-to-first-non-digit-decimal-charcater#63032126

Andrus.

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